40x^2-40.1x+6=0

Solution for 40x^2-40.1x+6=0 equation:

40x^2-40.1x+6=0

a = 40; b = -40.1; c = +6;
Δ = b2-4ac
Δ = -40.12-4·40·6
Δ = 648.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40.1)-\sqrt{648.01}}{2*40}=\frac{40.1-\sqrt{648.01}}{80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40.1)+\sqrt{648.01}}{2*40}=\frac{40.1+\sqrt{648.01}}{80}
$